Final answer:
At time t = 3/4 T, an object in SHM is at its maximum negative displacement and momentarily at rest, which corresponds to option 1 of the statements provided.
Step-by-step explanation:
An object in simple harmonic motion (SHM) with period T undergoes a complete cycle every T seconds. If released from maximum positive displacement at t = 0, it would reach the equilibrium position at t = T/4, continue to the maximum negative displacement at t = T/2, and then return towards equilibrium, passing through the equilibrium position again at t = 3T/4.
At t = 3/4 T, the object has completed three-quarters of a period. Since it takes half a period (T/2) to go from one extreme of motion to the other, t = 3T/4 represents the moment just before the object reaches the maximum displacement on the next half of the cycle. At this point (3/4 T), the object is therefore momentarily at rest at maximum negative displacement.
Accordingly, the correct description of the object's motion at t = 3/4 T is this: (1) The object is momentarily at rest at maximum negative displacement.