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TIME SENSITIVE

(2,6)
x-y=4

(a) write an equation of the line that passes through the point and is parallel to the given line
(b) write an equation of the line that passes through the point and is perpendicular to the given line

User Wez Furlong
by
2.8k points

1 Answer

21 votes
21 votes

Answer:

(a) Equation of parallel line is y = x + 4

(b) Equation of perpendicular line is y = - x + 8

Explanation:

Given line is

x - y = 4

Rewrite this as

x - 4 = y

or

y = x - 4

This is the equation of a line in slope intercept form which is generally

y = mx + b

where m is the slope and b the y-intercept

Here m = 1, b = -4

(a) A parallel line will have the same slope but a different y-intercept
So for starters we can write the equation of the parallel line as
y = x + b

Since this passes through (2,6) sub 2 for x and 6 for y to get

6 = 2 + b

==> b = 4

Equation of the line is
y = x + 4

(b) A perpendicular line will have as slope -1/m where m is the slope of the original line

Here m = 1, so -1/m = -1/1 = -1

Equation will be of the form
y = -x + b

Since this also passes through (2,6)
6 = -2 + b

==> b = 6 + 2 = 8

Equation of perpendicular line is
y = -x + 8

User AswinRajaram
by
3.2k points
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