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Consider this code:

cout << numeric_limits::max() << '\\';
Select the true statement.

a) It prints the minimum value of a short integer.
b) It prints the maximum value of a short integer.
c) It results in a compilation error.
d) It prints the size of a short integer.

1 Answer

5 votes

Final answer:

The code results in a compilation error because it's missing the template argument for numeric_limits. To correct this, specify a type like short: numeric_limits::max().

Step-by-step explanation:

The correct statement is c) It results in a compilation error. The reason for this is that the code snippet provided is missing the template argument required by numeric_limits. The numeric_limits is a template class that requires you to specify a type for which you want to know the limits, such as int, double, or short. For example, to print the maximum value of a short integer, you should write cout << numeric_limits::max() << '\\';. Without the specification of a type, the compiler doesn't know for which data type to get the maximum value, hence it will throw a compilation error.

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