Question

You have two cans of paint, Can A and Can B. Can A contains 80% red paint and 20% blue. Can B contains half blue and half red. How much blue paint should be added to 3 liters of Can A to make it the same as Can B?

Answer 1

To make Can A have the same composition as Can B, 0.9 liters of blue paint needs to be added to the 3 liters of Can A.

Step-by-step explanation:

To determine how much blue paint should be added to 3 liters of Can A to make it the same as Can B, we need to first understand that Can B consists of 50% blue paint and 50% red paint. Since Can A is 80% red and 20% blue, adding more blue paint will adjust the ratio.

Currently, Can A has 3 liters, with 0.6 liters of blue paint (20% of 3 liters). To have an equal amount of blue and red paint like Can B, we would need 1.5 liters of blue paint because half of 3 liters is 1.5 liters. To achieve this, we subtract the amount already present (0.6 liters) from the desired amount (1.5 liters).

The calculation is as follows: 1.5 liters (desired blue paint) - 0.6 liters (existing blue paint) = 0.9 liters. Therefore, you need to add 0.9 liters of blue paint to Can A to make it have the same composition as Can B.

Answer 2

0.9 liters.

Step-by-step explanation:

The difference between 20% of 3 and 50% of 3 is 30%. 30% of 3 liters is 0.9 liters so this is what you add to can A.