Question

A single family has a general lighting load of 6,000 VA. The smallest number of 15 amp branch circuit is:

1. Two
2. Three
3. Four
4. Five

Answer 1

The smallest number of 15 amp branch circuits required for a general lighting load of 6,000 VA is not available among the given options.

Step-by-step explanation:

The general lighting load of 6,000 VA can be used to determine the number of 15 amp branch circuits needed. To find the number of circuits, we can use the formula:

Number of Circuits = (Total VA) / (Ampere Rating)

Plugging in the values, we get:

Number of Circuits = (6,000 VA) / (15 amp) = 400 circuits

Therefore, the smallest number of 15 amp branch circuits required would be 400, which is not listed as one of the options. So the correct answer is not provided in the options given.