Question

What is the remainder of 2x^2+7x -39/x-7

Answer 1

108

Explanation:

To find the remainder of the polynomial
`\sf (2x^2+7x-39)/(x-7)`, we can use the Remainder Theorem.

According to the Remainder Theorem, if we divide a polynomial
`\sf f(x)` by
`\sf x - c`, the remainder is equal to
`\sf f(c)`.

In this case,
`\sf c = 7`.

So, substitute
`\sf x = 7` into the polynomial:

`\sf \begin{aligned}\text{Remainder} &= 2(7)^2 + 7(7) - 39 \\\\&= 98 + 49 - 39 \\\\&= 108.\end{aligned}`

Therefore, the remainder is 108.

Answer 2

Explanation:

To find the remainder of 2x^2 + 7x - 39 divided by x - 7, we can use the Remainder Theorem. This theorem states that for a polynomial f(x) and a number a, the remainder when f(x) is divided by x - a is equal to f(a).

In this case, our polynomial f(x) = 2x^2 + 7x - 39 and our divisor is x - 7. So, we need to find the value of f(7):

f(7) = 2(7)^2 + 7(7) - 39
f(7) = 98 + 49 - 39
f(7) = 108

Therefore, the remainder when 2x^2 + 7x - 39 is divided by x - 7 is 108.