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9 votes
9 votes
Two pools are being filled with water. To start, the first pool contains 707 liters of water and the second pool is empty. Water is being added to the first pool at a

rate of 18.25 liters per minute. Water is being added to the second pool at a rate of 43.5 liters per minute.

After how many minutes will the two pools have the same amount of water?

How much water will be in each pool when they have the same amount?

User Rajeev Varshney
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2.5k points

1 Answer

8 votes
8 votes

Let t be the number of minutes that have passed since water started being added to the two pools. The total amount of water in the first pool after t minutes is 707 + 18.25t liters, and the total amount of water in the second pool after t minutes is 43.5t liters. We are looking for the value of t that makes these two quantities equal, which represents the time when the two pools have the same amount of water.

We can set the two quantities equal to each other and solve for t to find the value of t that makes the two pools have the same amount of water:

707 + 18.25t = 43.5t

707 = 25.75t

t = 27.5

Therefore, after 27.5 minutes, the two pools will have the same amount of water.

To find the amount of water that will be in each pool when they have the same amount of water, we can substitute the value of t that we found above into the expressions for the total amount of water in each pool:

First pool: 707 + 18.25 * 27.5 = 707 + 501.875 = 1208.875

Second pool: 43.5 * 27.5 = 1208.875

Therefore, when the two pools have the same amount of water, each pool will have 1208.875 liters of water.

User Ivan Gonzalez
by
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