Final answer:
To solve the system of equations, we can use the elimination method. By multiplying the equations and subtracting them, we find that x = 2 and y = 6. Therefore, the solution is (2, 6).
Step-by-step explanation:
To solve the system of equations 5x + 10y = 70 and 8x + 8y = 64, we can use either substitution or elimination method. Let's use the elimination method:
Multiply the second equation by 5 to make the coefficients of x in both equations equal:
40x + 40y = 320
Now subtract the first equation from the second equation:
(40x + 40y) - (5x + 10y) = 320 - 70
35x + 30y = 250
Now we have a new system of equations:
35x + 30y = 250 and 5x + 10y = 70
Next, multiply the second equation by 7 to make the coefficients of y in both equations equal:
35x + 70y = 490
Now subtract the first equation from the second equation:
(35x + 70y) - (35x + 30y) = 490 - 250
40y = 240
Divide both sides of the equation by 40:
y = 6
Substitute the value of y back into the first equation:
5x + 10(6) = 70
5x + 60 = 70
5x = 10
Divide both sides of the equation by 5:
x = 2
The solution to the system of equations is (2, 6), so the correct answer is (2, 6).