Question

URGENT PLEASE

Solve 2sinx+1=0 for x, where 0≤x≤360°.

Answer 1

• B) 210°, 330°

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Given equation:

• 2sinx + 1 = 0

Solve it in the interval [0°; 360°]:

• 2sinx + 1 = 0
• 2sinx = - 1
• sinx = - 1/2

• x = 360° - 30° ⇒ x = 330° within given interval
• x = 180° + 30° ⇒ x = 210° within given interval

Correct choice is B.