Find the first term of an arithmetic sequence f(10)=5 and f(19)=-31 show work please

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Answer:

Explanation:

Let the common difference be
d/tex] and the first term be [tex]a .

$f(10)=5 \implies a+9d=5 \\ \\ f(19)=-31 \implies a+18d=-31 \\ \\ \therefore -9d=36 \implies d=-4 \\ \\ \therefore a+9(-4)=5 \implies a=41$

Kumaheiyama answered Sep 21, 2023

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