Question

The product of two consecutive positive integers is 812. What is the value of the lesser integer? a. 7 b. 28 c. 58 d. 203

Answer 1

B

Explanation:

Answer 2

The value of the lesser integer is
`28`

Explanation:

Let two consecutive positive integers be
`x,x+1`.

Product of two consecutive positive integers =
`x(x+1)=x^2+x`

Also, product of two consecutive positive integers is 812

So,

`x^2+x=812\\x^2+x-812=0\\x^2+29x-28x-812=0\\x(x+29)-28(x+29)=0\\(x-28)(x+29)=0\\x=28,-29`

As
`x` is a positive integer,

`x=-29` is rejected.

So,

`x=28\\x+1=28+1=29`

Two positive integers are
`28,29`

The value of the lesser integer is
`28`