Question

If a rocket initially at rest accelerates at a rate of 50 m/s² for one minute, its speed will be

Answer 1

3000 m/s

Step-by-step explanation:

Acceleration is changes in velocity over change in time which can be expressed mathematically as:

`\displaystyle{\vec a = (\Delta \vec v)/(\Delta t)}`

In basic physic, we express the equation as:

`\displaystyle{\vec a =(\vec v - \vec u)/(t)}`

Sometimes the equation is expressed without vector arrows. Each terms represent each meanings:

• u = initial velocity
• v = final velocity
• t = time
• a = acceleration

We know that initial velocity is 0 m/s because it’s already given in the problem, acceleration is 50 m/s² and time is 60 seconds.

Substitute in the formula:

`\displaystyle{50 \ \, m/s^2= \frac{\vec v-0 \ \, \text{m/s}}{60 s}}\\\\\displaystyle{50 \ \, m/s^2= (\vec v)/(60 s)}\\\\\displaystyle{3000 \ \, m/s=\vec v}`

Therefore, speed is 3000 m/s