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Graph a line that goes through the point (6,-6) with the a slope of -1/2​

User Cody Moniz
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1 Answer

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12 votes

Answer:

see below

Explanation:

Find the equation of the line in slope-intercept form with the properties:

slope: m = -1/2

point: p_1 = (6, -6)

Substitute the slope m = -1/2 and point (x_1, y_1) = (6, -6) into the point-slope equation y - y_1 = m (x - x_1):

y - (-6) = -1/2 (x - 6)

-1/2 (x - 6) = (6 - x)/2:

6 + y = (6 - x)/2

Subtract 6 from both sides:

y = (6 - x)/2 - 6

(6 - x)/2 - 6 = -x/2 - 3:

y = -3 - x/2

Distribute: (6 - x)/2 = 3 - x/2:

Answer: y = -x/2 - 3

Graph a line that goes through the point (6,-6) with the a slope of -1/2​-example-1
User Amit Thaper
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