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What is the maximum torque on a 140-turn square loop of wire 13.0 cm on a side that carries a 60.0-a current in a 1.80-t field?

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Final answer:

The maximum torque on a 140-turn square loop of wire, carrying a current in a magnetic field, is 254.52 Nm.

Step-by-step explanation:

The question involves finding the maximum torque on a square loop carrying a current in the presence of a magnetic field. This calculation is based on the formula τ = nIABsin(θ), where τ is torque, n is the number of turns, I is the current, A is the area of the loop, B is the magnetic field strength, and θ (theta) is the angle between the normal to the loop and the magnetic field. For maximum torque, sin(θ) equals 1, as this occurs when θ is 90°.

The area, A, of a square loop is given by the formula A = l², where l represents the length of one side of the square. To calculate the maximum torque in this case, we use the given values: n = 140 turns, l = 13.0 cm (converted to meters as 0.13 m for SI units), I = 60.0 A, and B = 1.80 T. Therefore, A is (0.13 m)² and the maximum torque formula simplifies to τ = 140 × 60.0 A × (0.13 m)² × 1.80 T = 254.52 Nm.

User Martin Scharrer
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