Question

What is the specific heat capacity of a metal if a 6.91 g sample of the metal has a temperature change of 63.5 deg c while releasing 351 j of heat to the water the hot metal sample was placed in.

Answer 1

The specific heat capacity of a metal can be calculated using the formula Q = mcΔT, where Q is the heat transferred, m is the mass of the metal, c is the specific heat capacity of the metal, and ΔT is the change in temperature. In this case, the specific heat capacity of the metal is approximately 0.087 J/g°C.

Step-by-step explanation:

The specific heat capacity of a metal can be calculated using the formula:

Q = mcΔT

Where:

• Q is the heat transferred (in Joules)
• m is the mass of the metal (in grams)
• c is the specific heat capacity of the metal (in J/g°C)
• ΔT is the change in temperature (in °C)

In this case, we have a 6.91 g sample of metal, which releases 351 J of heat while the temperature changes by 63.5 °C.

Plugging these values into the equation:

351 J = (6.91 g) * c * 63.5 °C

Dividing both sides of the equation by (6.91 g * 63.5 °C), we can solve for c:

c = 351 J / (6.91 g * 63.5 °C)

So, the specific heat capacity of the metal is approximately c = 0.087 J/g°C.