Final answer:
The student's question involves finding components of a velocity vector using trigonometric functions within the context of physics. To find the components, one would use the given sine and cosine values along with the velocity. The provided operation '53°× 40m/s' is not a standard calculation and needs clarification.
Step-by-step explanation:
The question appears to involve the application of trigonometry in a physics context, specifically relating to vector multiplication involving an angle and a velocity. When the student mentions '53°× 40m/s', it seems they're attempting to find a component of a velocity vector that makes an angle of 53 degrees with the horizontal.
However, the operation as written is not clear. To solve a problem like this, one would generally use sine or cosine functions to find the components. For instance, the horizontal component (Vx) of the velocity would be V × cos(53°), and the vertical component (Vy) would be V × sin(53°). With the given values of sin(53°) = 0.8 and cos(53°) = 0.6, the calculations would be 40 m/s × 0.6 for the horizontal component and 40 m/s × 0.8 for the vertical component.
If the student is trying to determine the resultant velocity vector magnitude or a specific component, they would need to clarify the direction or the component they are interested in.