Final answer:
The Ka equation for the given reaction NH₄ + (aq) + H₂O(l) ⇌ H₃O + (aq) + NH₃(aq) is Ka = [H₃O+][NH₃]/[NH₄+]. The equilibrium constant Ka represents the acidity of a weak acid. In this reaction, NH₄+ acts as a weak acid and donates a proton to water, forming H₃O+ and NH₃.
Step-by-step explanation:
The Ka equation for the given reaction NH₄ + (aq) + H ₂O(l) ⇌ H₃O + (aq) + NH₃(aq) is Ka = [H₃O+][NH₃]/[NH₄+].
The equilibrium constant Ka represents the acidity of a weak acid. In this reaction, NH₄+ acts as a weak acid and donates a proton to water, forming H₃O+ and NH₃. The Ka expression is obtained by taking the concentration of the products (H₃O+ and NH₃) divided by the concentration of the reactant (NH₄+).
For example, if the concentration of H₃O+ is 0.1 M and the concentration of NH₃ is 0.2 M, and the concentration of NH₄+ is 0.3 M, the Ka value would be [0.1][0.2]/[0.3] = 0.067 M.