Question

A boy visiting New York City views the Empire State building from a point on

the ground, A, which is 940 feet from foot, C, of the building. The angle of
elevation of the top, B, of the building as seen by the boy is 53 degrees. Find the
height of the building to the nearest foot.

Answer 1

To find the height of the Empire State Building, we can use trigonometry and the concept of similar triangles. By setting up a right triangle and using the tangent function, we can calculate the height to be approximately 1248 feet.

Step-by-step explanation:

To find the height of the Empire State Building, we can use trigonometry and the concept of similar triangles. We can set up a right triangle where the height of the building is the vertical side, the horizontal distance from the boy to the building is the horizontal side, and the angle of elevation is the angle opposite the vertical side. We can use the tangent function to calculate the height:

tan(angle) = opposite/adjacent

In this case, tan(53 degrees) = height/940 feet

So, height = tan(53 degrees) * 940 feet

Using a calculator, we can find that tan(53 degrees) ≈ 1.327

Therefore, height ≈ 1.327 * 940 feet ≈ 1247.98 feet

So, the height of the Empire State Building to the nearest foot is 1248 feet.

Answer 2

49,820

Step-by-step explanation:

so what you were going to do first is you're going to do 940 * 53 there is which equals 2820 and then you're going to do turtle messes so then you're going to do 5 * 0 which equals zero then five times for which equals 20 + 5 * 9 which equals 45 + 2 which 45 + 2 equals 47 so you have 2820 + 47000 which equals 49,820