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What is the equation for the line that passes through the points (3, 4) and (5,8)

User CheGueVerra
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1 Answer

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17 votes

The equation of a line is typically given in the form y = mx + b, where m is the slope of the line and b is the y-intercept (the point where the line crosses the y-axis). To find the equation of the line that passes through the points (3, 4) and (5, 8), we need to first calculate the slope of the line.

The slope of a line is given by the formula m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of two points on the line. In this case, we have:

m = (8 - 4) / (5 - 3) = 4/2 = 2

Now that we know the slope of the line, we can use one of the given points to find the y-intercept. Let's use the point (3, 4). If we plug the values of x and y into the equation y = mx + b, we get:

4 = 2 * 3 + b

4 = 6 + b

-2 = b

Therefore, the equation of the line that passes through the points (3, 4) and (5, 8) is:

y = 2x - 2

User Fchauvel
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