447,206 views
39 votes
39 votes
A bag contains 1 gold marbles, 6 silver marbles, and

28 black marbles. Someone offers to play this game:
You randomly select one marble from the bag. If it
is gold, you win $3. If it is silver, you win $2. If it is
black, you lose $1.
What is your expected value if you play this game?

User Smheidrich
by
3.3k points

1 Answer

15 votes
15 votes

Explanation:

the expected value is the sum of all values multiplied by their corresponding probabilities.

and a probability is always

desired cases / totally possible cases.

in the bag are

28 + 6 + 1 = 35 marbles

the probability to pull the gold is

1/35

the probability to pull a silver is

6/35

the probability to pull a black is

28/35 = 4/5

the expected value = $3×1/35 + $2×6/35 - $1×28/35 =

= 3/35 + 12/35 - 28/35 =

= -13/35 = -0.371428571... ≈

≈ -$0.37

that means (like with all games of that kind like all casino games) the bank will win in the long run.

your only chance to win is to play very few times and get a winner by pure chance. the longer you play you might actually hit a winner somewhere in between, but the surer you still lose in total.

User Meena Alfons
by
3.2k points