Question

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $30 and same-day tickets cost $35. For one performance, there were 55 tickets sold in all, and the total amount paid for them was $1825. How many tickets of each type were sold?​

Answer 1

sorry i messed up my first calculations, currently recalculating

Explanation:

Answer 2

• 35 same-day tickets
• 20 advance tickets

Explanation:

You want the number of $30 advance tickets and $35 same-day tickets sold, when a total of 55 tickets were sold for $1825.

Setup

Let s represent the number of same-day tickets sold. Then 55-s is the number of advance tickets sold, and total revenue is ...

35s +30(55 -s) = 1825

Solution

5s = 175 . . . . . . Simplify, subtract 1650

s = 35

55-s = 30

35 same-day and 30 advance tickets were sold.