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43 votes
43 votes
Solve for x using the quadratic formula: x² - 6x + 9 = 0

X=
-b± √b²-4ac
2a
Ox=6
Ox=3
Ox=1
Ox=0

User Stefan Glienke
by
2.6k points

1 Answer

10 votes
10 votes

Answer:


\huge{ \boxed{x = 3}}

Explanation:


{x}^(2) - 6x + 9 = 0

Using the quadratic formula that's,


\bold{x = \frac{ - b \pm \sqrt{ {b}^(2) - 4ac } }{2a}} \\

Comparing the equation to the general form of a quadratic equation ( ax² + bx + c), we have.


a = 1 \\ b = - 6 \\ c = 9

Substituting the values into the formula we have.


x = \frac{- ( -6) \pm \sqrt{( - {6})^(2) - 4(1)(9) } }{2(1)} \\ x = (6 \pm √(36 - 36) )/(2) \\ x = ( 6 \pm√(0) )/(2) \\ x = (6)/(2) \: \: \: \: \: \\ \\ x = 3 \: \: \: \: \: \: \: \: \: \: \: \: \:

We have the final answer as

x = 3

User Szarpul
by
2.7k points