Question

Flag In reaching her destination, a backpacker walks with an average velocity of 1.34 m/s, due west. This average velocity results because she hikes for 6.44 km with an average velocity of 2.68 m/s, due west, urns around, and hikes with an average velocity of 0.447 m/s, due east. (a) How far east did she walk? (b) If she did not turn around and walked due east, how many hours would it take her to reach her destination with an average velocity of 1.34m/s due west?

Answer 1

`s_2=-806m`

Step-by-step explanation:

From the question we are told that

Velocity 1
`v=1.34m/s \angle west`

Distance
`d=6.44km=>6440m`

Velocity 2
`v_3=2.68m/s`

Velocity 3
`v_3=0.447m/s \angle east`

Generally the equation for VT is mathematically given by

`VT=v_1t_1 +V_2t_2`

`VT=2.68(2400)-0.447t_2`

`1.34t_1+1.34t_2=2.68(2400)-0.447t_2`

`t_2=1804s`

Therefore

`s_2=v_2t_2=(-0.447)(1804)`

`s_2=-806m`