Question

Han estado ubicada a 120cm de 1 poste vertical de 200cm de alto. Cuando levanta la Vista puede ver la parte más Alta de 1 edificio. Ella sabe que el edificio se encuentra a 1 000cm de poste. Sus ojos están a 150cm del terreno. ¿Cuál es la altura del edificio?​

Answer 1

The height of the building is calculated using the concept of similar triangles and the given dimensions. By setting up a proportion and solving for the height of the building, we find that it is approximately 616.67cm high.

Step-by-step explanation:

To calculate the height of the building the student is looking at, we need to use the concept of similar triangles. This is a mathematics problem that can be solved by creating two triangles that share one angle, where one triangle is formed by the student, the pole, and the line of sight from the student's eyes to the top of the pole, and the other triangle is formed by the student, the building, and the line of sight from the student's eyes to the top of the building.

We create a proportion between the two triangles:

(Height of the pole - Height of the student's eyes) / Distance from student to pole = (Height of the building - Height of the student's eyes) / (Distance from student to building + Distance from pole to building)

Plugging in the numbers we have we get:

(200cm - 150cm) / 120cm = (Height of the building - 150cm) / (120cm + 1000cm)

The equation simplifies to:

50cm / 120cm = (Height of the building - 150cm) / 1120cm

Solving for the height of the building gives us:

50/120 = (Height of the building - 150)/1120

Height of the building - 150 = (50 * 1120) / 120

Height of the building = (50 * 1120) / 120 + 150

Height of the building = 466.67cm + 150cm

Height of the building = 616.67cm

Therefore, the height of the building the student is looking at is approximately 616.67cm.