Question

PLS HELP NEED URGENT What is the value of g, the gravitational field strength, at the surface of the planet Venus?

Round your answer to two decimal places

Answer 1

8.83 N/kg

Step-by-step explanation:

To solve this problem we can use the formula:

`g=G(M)/(r^(2) )` which describes the field strength at a certain distance from a body (where g=gravitational field strength, G=Gravitational constant, M=Mass of planet, and r=distance from center of planetary mass).

We are given the information that the radius of Venus is 6.073 x 10^6m and its mass is 4.88x10^24kg.

We are also given the gravitational constant.

Since the radius of a planet is equal to the distance between the center of the planet to its surface we can use this value for 'r'.

Therefore we now have all the information we need and so we can plug these values into the equation to solve for the gravitational field strength:

`g=(6.67*10^(-11))((4.88*10^(24)))/((6.073*10^(6))^(2))`

`g=(6.67*10^(-11))((4.88*10^(24)))/(3.688*10^(13))`

`g=(6.67*10^(-11))*(1.323*10^(11))`

`g=8.83Nkg^(-1)` (to 2.d.p)