Final answer:
In nonpotable water systems, chlorine is used for disinfection and should not exceed 3.0 ppm. For chlorination of a 5,000 gal pool, roughly 59.8 grams of chlorine is needed to reach this concentration.
Step-by-step explanation:
Where chlorine is used for disinfection in nonpotable water systems, the water shall contain not more than 3.0 ppm of chloramines or free chlorine. To achieve this concentration in a typical 5,000 gal pool, which contains approximately 21,200 kg of water, one must first convert gallons to liters (1 gallon = 3.78541 liters) and then calculate the mass of chlorine needed based on the volume of the pool and the desired ppm concentration.
To calculate the required mass of chlorine to obtain a concentration of 3.0 ppm in a pool, use the formula: Mass of Chlorine (g) = Concentration (ppm) × Volume of Water (L) × (1 gram/1,000,000 ppm). For the given 5,000-gallon pool, the mass of chlorine required is approximately 59.8 grams.