Question

Refrigerant 134a is compressed from 2 bar, saturated vapor, to 10 bar, 90°C in a compressor operating at steady state. The mass flow rate of refrigerant entering the compressor is 7 kg/min, and the power input is 10.85 kW. Kinetic and potential energy effects can be neglected.

a. Determine the rate of heat transfer, in kW.

Answer 1

The rate of heat transfer in this process is 10.85 kW ,the rate of heat transfer is equal to the power input, which is 10.85 kW. Therefore, the rate of heat transfer is 10.85 kW.

Step-by-step explanation:

Given that Refrigerant 134a is compressed from 2 bar, saturated vapor, to 10 bar, 90°C in a compressor operating at steady state, and the mass flow rate of refrigerant entering the compressor is 7 kg/min, and the power input is 10.85 kW, we can calculate the rate of heat transfer.

To calculate the rate of heat transfer, we can use the first law of thermodynamics, which states that the rate of heat transfer is equal to the rate of work input plus the rate of change of internal energy.

Since the process is operating at steady state, there is no change in internal energy, so the rate of heat transfer is equal to the rate of work input.

In this case, the rate of heat transfer is equal to the power input, which is 10.85 kW. Therefore, the rate of heat transfer is 10.85 kW.