Final answer:
The structure and formation of a compound resulting from an adduct heated in methanol depend on the specific adduct, but generally involves a double displacement or esterification reaction. Examples of reactions provided are acid-base reactions resulting in calcium acetate and water, and an esterification reaction to form methyl acetate.
Step-by-step explanation:
The question asks for the structure of a compound and a balanced chemical equation for its formation when an adduct is heated too long in methanol (CH₃OH) as a recrystallization solvent. Without specific details of the adduct, we can focus on the general process of a double displacement reaction that has been provided in the question.
The unbalanced reaction is given as CH₃CH₂CO₂H(aq) + Ca(OH)₂(aq) → (CH₃CH₂CO₂)₂Ca(aq) + H₂O(l). This is an example of an acid-base reaction where the carboxylic acid (acetic acid) reacts with a base (calcium hydroxide) to form calcium acetate and water. When heated in methanol, it suggests that perhaps esterification could occur, yielding a different product such as methyl acetate.
For the provided esterification reaction, the balanced equation is C₂H₅OH + CH₃CO₂H = CH₃CO₂C₂H₅ + H₂O, where ethanol reacts with acetic acid to produce methyl acetate and water. The formation of calcium acetate from acetic acid and calcium hydroxide provides an example of a standard enthalpy of formation calculation for the compound.