Question

Solve the equation: p² -2p+17=0 Fully simplify all answers, including identifying cases where there are no solutions. Please proceed with the solution.

Answer 1

To solve the equation p² -2p+17=0, substitute the values of a, b, and c into the quadratic formula and simplify to find the solutions. In this case, the equation has no real solutions.

Step-by-step explanation:

To solve the equation p² -2p+17=0, we can use the quadratic formula. First, let's identify the values of a, b, and c in the equation. Here, a = 1, b = -2, and c = 17. Plugging these values into the quadratic formula, we get:

`x = (-b ± √(b² - 4ac)) / (2a)`

Substituting the values, we have:

`x = (-(-2) ± √((-2)² - 4(1)(17))) / (2(1))`

x = (2 ± √(4 - 68)) / 2

x = (2 ± √(-64)) / 2

Since the value inside the square root is negative, there are no real solutions to this equation.