Question The general form of a hyperbola is 6x2−5y2+12x+50y−149=0.

Cfbarbero asked Nov 9, 2023

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Cfbarbero asked Nov 9, 2023

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Answer:the general form of a hyperbola is 6x^2-5y^2+12x+50y-149=0 the answer is (x+1)^2/5 -((y-5)^2/6=1

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Celal Selcan answered Nov 16, 2023

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