Question

A flask is charged with 2.14 atm of pressure with a mixture of Heliox containing 0.52 moles of oxygen and 0.217 moles of helium? What is the partial pressure of helium in atm in the flask?

Answer 1

The partial pressure of helium in the flask can be determined using Dalton's Law of Partial Pressures. By calculating the ratio of the number of moles of helium to the total number of moles and multiplying by the total pressure, we find that the partial pressure of helium is approximately 0.630 atm.

Step-by-step explanation:

We can find the partial pressure of helium in the flask by using Dalton's Law of Partial Pressures, which states that the total pressure of a gas mixture is the sum of the partial pressures of each individual gas in the mixture. The formula for the partial pressure of a gas is:

Pgas = (ngas / ntotal) × Ptotal

Where Pgas is the partial pressure of the gas, ngas is the number of moles of the gas, ntotal is the total number of moles of gas, and Ptotal is the total pressure of the gas mixture.

For helium:

• nHe = 0.217 moles (number of moles of helium)
• ntotal = 0.52 + 0.217 moles
• = 0.737 moles (total number of moles of gas)
• Ptotal = 2.14 atm (total pressure given)

So, the partial pressure of helium (PHe) is:

PHe = (0.217 moles / 0.737 moles) × 2.14 atm

Now, calculate PHe:

PHe = 0.2946 × 2.14 atm

PHe = 0.630248 atm

The partial pressure of helium in the flask is approximately 0.630 atm.