Final answer:
The vertical speed (y-direction) of the ball at the peak of its trajectory is 0 mi/h. The vertical speed of the ball at the peak of its trajectory is 0 mi/h because gravity decelerates the vertical component of the velocity to zero at that point.
Step-by-step explanation:
To determine the vertical speed (y-direction) of the ball at the peak of its trajectory, we can use the fact that the vertical motion of a projectile is affected by gravity. The initial speed along the y-direction is given as 30 mi/h. At the peak of its trajectory, the vertical speed will be zero since it momentarily stops before falling back down.
This is because the force of gravity pulls the ball downwards and reduces its vertical speed to zero. Therefore, the vertical speed (y-direction) of the ball at the peak of its trajectory is 0 mi/h.
The vertical speed of the ball at the peak of its trajectory is 0 mi/h because gravity decelerates the vertical component of the velocity to zero at that point.
The vertical speed of a ball at the peak of its trajectory in projectile motion is 0 mi/h. At the peak of its path, the vertical component of a projectile's velocity is always zero because gravity has decelerated it to zero before it starts to accelerate the object downward on its descent.
This holds true regardless of any horizontal motion the object may have, such as the 50 mi/h motion along the x-direction for this problem.