11.6k views
1 vote
\(4^{2}-9x+8\) need help

User Dfreeman
by
7.3k points

1 Answer

6 votes

The values of x are 1 and 8.

How to solve quadratic equation.

Given that

x² - 9x + 8 = 0

Let's factorize the quadratic equation

Find 2 numbers whose product is 8(the constant number in the equation) and whose sum is -9(the coefficient of x in the equation)

so, let's consider

-1 and -8

product = -1 * -8 = 8

sum = -1 + (-8) = -1 - 8 = -9

x² -9x + 8 = 0

Split the coefficient of x

x² - x - 8x +8 = 0

Factorize

x(x - 1) -8(x -1) = 0

(x - 8)(x - 1) = 0

Equate each expression to zero

x - 8 = 0 or x - 1 = 0

x = 8 or x = 1

Therefore, the values of x are 1 and 8.

Complete question

\(4^{2}-9x+8\) need help-example-1
User Gantoine
by
8.1k points