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The first eleven non-negative perfect cubes are...

A) 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, 1331
B) 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121
C) 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11
D) 0, 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000

User Elan
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Final answer:

The first eleven non-negative perfect cubes are 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, and 1331. To find perfect cubes, you raise a number to the power of 3 or cube the digit term in the usual way and multiply the exponent by 3.

Step-by-step explanation:

The first eleven non-negative perfect cubes are:

A) 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, 1331

To find perfect cubes, you raise a number to the power of 3. For example, 2^3 = 8, 3^3 = 27, 4^3 = 64, and so on. You can also cube the digit term in the usual way and multiply the exponent of the exponential term by 3. It's important to understand the concept of integer powers to find perfect cubes. Math provides many paths to the same answer, so it's useful to check and reinforce your understanding.

User ALUFTW
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