Final answer:
As the temperature of a blackbody radiator increases, the most intense wavelength of light emitted decreases, shifting the peak of the blackbody curve towards shorter wavelengths in the spectrum.
Step-by-step explanation:
When the temperature of a blackbody radiator is increased, the most intense wavelength of light emitted by the blackbody decreases. According to Wien's displacement law, the wavelength of peak emission is inversely proportional to the temperature. Hence, as the temperature increases, the wavelength of the most intense radiation (peak wavelength) shifts to shorter values. This shift causes the color of the radiation to move toward the blue end of the spectrum, making the radiation appear 'whiter' as the temperature rises.
An increase in temperature means that there is more energy available for the blackbody to emit, and this results in a higher intensity of radiation across the spectrum, especially at shorter wavelengths. Thus, the peak of the blackbody curve shifts to the left, representing a decrease in the wavelength of the most intense radiation.
The correct answer to the question is therefore:
d. The wavelength of the most intense radiation will decrease.