Question

Given the following formula, solve for v.

8 = 1/2 a^2v + c

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Answer 1

`v = (16-2c)/(a^(2) )`

Explanation:

Original equation

`8 = (1)/(2)a^(2) v + c`

Multiply both sides by 2 to get rid of fraction

`16 = a^(2)v + 2c`

Get constant on right,
`a^(2) v` on left

`-a^(2)v = 2c - 16`

Divide both sides by
`a^(2)`

`v = (16 - 2c)/(a^(2) )`