Final answer:
To find the current drawn by the kettle from a 120 V outlet with an 8.0 Ω resistance, Ohm's law I = V/R is used, yielding a current of 15 amperes.
Step-by-step explanation:
The student's question is concerning the amount of current a kettle draws from a 120 V outlet with a heating element resistance of 8.0 Ω (ohms). To find the current (I) drawn by the kettle, we apply Ohm's law, which is I = V/R, where V is the voltage and R is the resistance.
The kettle is operated with a 120 V supply, so we have:
- Voltage (V) = 120 V
- Resistance (R) = 8.0 Ω
Thus, the current I drawn by the kettle is:
I = V / R = 120 V / 8.0 Ω = 15 A
The kettle draws a current of 15 amperes (A) from the 120 V outlet.
To determine the current drawn by the kettle, we can use Ohm's Law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R):
I = V / R
Given that the voltage is 120 V and the resistance is 8.0 Q, we can substitute these values into the equation to find the current:
I = 120 V / 8.0 Q = 15 A
Therefore, the kettle draws a current of 15 A.