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Mrs. Bell has 16 boys and 88 girls signed up for dance class this summer. She wants to create identical teams that have the same number of boys on each team and the same number of girls on each team. What is the greatest number of teams Mrs. Belk can form?

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Final answer:

The greatest number of identical teams Mrs. Bell can form with 16 boys and 88 girls, ensuring each team has the same number of boys and girls, is eight teams.

Step-by-step explanation:

The question involves finding the greatest number of identical teams Mrs. Bell can form with 16 boys and 88 girls, where each team must have the same number of boys and the same number of girls. This is a greatest common divisor (GCD) problem in mathematics as we are searching for the largest number that evenly divides into both 16 and 88.

To solve this, we calculate the GCD of 16 and 88. The factors of 16 are 1, 2, 4, 8, and 16. The factors of 88 are 1, 2, 4, 8, 11, 22, 44, and 88. The greatest common divisor is the highest number that appears in both lists of factors, which is 8. Thus, Mrs. Bell can form eight teams with an equal number of boys and girls on each team. There would be 2 boys (16 boys ÷ 8 teams) and 11 girls (88 girls ÷ 8 teams) on each team.

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