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A coin is flipped 10 times and the results is recorded.Tyler is calculating the number of ways to toss no more than 2 heads using the expression 10c1+10c2 .What error did he make

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Final answer:

The error Tyler made is in not including the number of ways to toss 0 heads when calculating the number of ways to toss no more than 2 heads.

Step-by-step explanation:

Tyler made an error in his calculation of the number of ways to toss no more than 2 heads. The expression he used, 10c1+10c2, represents the number of ways to toss exactly 1 head plus the number of ways to toss exactly 2 heads. However, the question asks for the number of ways to toss no more than 2 heads, which includes tossing 0, 1, or 2 heads. To calculate this, you need to use the expression 10c0 + 10c1 + 10c2.

Let's break it down:

  1. 10c0 represents the number of ways to toss 0 heads, which is 1 way.
  2. 10c1 represents the number of ways to toss exactly 1 head, which is 10 ways.
  3. 10c2 represents the number of ways to toss exactly 2 heads, which is 45 ways.

Now, we can add up these values: 10c0 + 10c1 + 10c2 = 1 + 10 + 45 = 56 ways to toss no more than 2 heads. Therefore, the correct expression should be 10c0 + 10c1 + 10c2, not 10c1 + 10c2.

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