Question

In a chemical experiment, a student is given 100.0 mL of an unknown concentration calcium chloride solution. After adding excess 2.0 M sodium carbonate, 0.53 g of precipitate is recovered. Write the net ionic equation for the reaction and identify the precipitate.

Answer 1

The net ionic equation for the reaction between calcium chloride and sodium carbonate, forming a precipitate of calcium carbonate, is Ca2+(aq) + CO32-(aq) → CaCO3(s). The precipitate is calcium carbonate.

Step-by-step explanation:

The question asks us to write the net ionic equation for the reaction between calcium chloride and sodium carbonate and identify the precipitate. With an excess of 2.0 M sodium carbonate added to the calcium chloride solution, a precipitation reaction will occur, forming a solid precipitate of calcium carbonate (CaCO3).

The net ionic equation for this reaction is written below:

Ca2+(aq) + CO32-(aq) → CaCO3(s)

The identities of the spectator ions, Na+ and Cl-, are not included in the net ionic equation as they do not participate directly in the reaction.

Calcium carbonate is the substance that precipitates out of the solution, hence the recovered 0.53 g of precipitate is calcium carbonate.