Final answer:
The coefficient in front of the x² term in the given multiplication is 15.
Step-by-step explanation:
The question asks for the coefficient that would be in front of the term x² after performing the multiplication 5x(3x² + 4x + 3). The process of distribution, or multiplying each term inside the parentheses by 5, gives us the new expression: 5 * 3x² + 5 * 4x + 5 * 3. This simplifies to 15x² + 20x + 15. Therefore, the coefficient in front of x² is 15.
To find the coefficient in front of the x² term in the multiplication 5x(3x² + 4x + 3), we need to distribute the 5 to each term inside the parentheses. This will result in 5 multiplied by 3x², 4x, and 3. The coefficient in front of x² will be the result of multiplying 5 with the coefficient of x² inside the parentheses, which is 3. Therefore, the coefficient in front of the x² term is 15.
The question asks for the coefficient that would be in front of the term x² after performing the multiplication 5x(3x² + 4x + 3). The process of distribution, or multiplying each term inside the parentheses by 5, gives us the new expression: 5 * 3x² + 5 * 4x + 5 * 3. This simplifies to 15x² + 20x + 15. Therefore, the coefficient in front of x² is 15.