Final answer:
The question pertains to the tension in a cable supporting a submerged ball, involving the application of Archimedes' principle, buoyancy, and density conversion in physics calculations.
Step-by-step explanation:
The question concerns the calculation of tension in a cable supporting a submerged solid ball in water, considering the physical principles of physics, specifically Archimedes' principle, density, and buoyancy. The spherical ball has a radius of 0.6 m and is made of plastic with a density of 48 kg/ml, and it is submerged at a depth of 0.9 m. The density of plastic must be converted into appropriate SI units to work with standard equations in physics. To calculate the tension, it's essential to determine the buoyant force acting on the submerged object, which is dependent on the density of water (1000 kg/m³) and the gravitational force (9.8 m/s²).
To begin calculation, we need to find the volume of the sphere using the formula V = 4/3 π r³ and then find the weight of the ball by multiplying its density with its volume. After that, the buoyant force exerted by the water can be calculated by multiplying the density of water with the volume of the submerged part of the ball and the gravitational acceleration. The tension in the cable can then be found by subtracting the buoyant force from the weight of the submerged ball.
It's important to note that the original question has incorrect information regarding the density units, and references to surface tension and angular measurements are irrelevant to this specific problem. In such cases, we must focus on the central problem, which involves Archimedes' principle and the concept of buoyancy.