Question

Arrange the following decimals in ascending order of the place values 123.45628 : 3.802 : 111.414 : 762.919

Answer 1

To arrange the given decimals in ascending order, compare each digit from the highest place value down. The ascending order is 3.802, 111.414, 123.45628, and 762.919.

Step-by-step explanation:

To arrange the decimals 123.45628, 3.802, 111.414, and 762.919 in ascending order, we must compare each of their place values. Starting from the largest place value, which is the hundreds for these numbers, we compare all the digits in the same position:

• 3.802 has 0 hundreds.
• 111.414 has 1 hundred.
• 123.45628 has 1 hundred (same as 111.414, so we look at the next highest place value, which is the tens place. 123.45628 has 2 tens, which is more than the 1 ten in 111.414).
• 762.919 has 7 hundreds.

After comparing the place values, the decimals in ascending order are: 3.802, 111.414, 123.45628, and 762.919.