Question

A golf ball of mass 0.03 kg initially at rest is struck by a golf club and given a speed of 50m/s along the horizontal. if the club and the ball were in contact for 0.002is,what average force is acted on the ball? show whether or not gravity should be accounted for​.

Answer 1

The average force acted on the golf ball is 1500 N. Gravity should not be accounted for.

Step-by-step explanation:

To determine the average force exerted on the golf ball, we can use the equation:

F = (m * (Vf - Vi)) / t

• F is the force
• m is the mass of the golf ball
• Vf is the final velocity of the golf ball
• Vi is the initial velocity of the golf ball
• t is the time of contact

In this case, the mass of the golf ball is 0.03 kg, the initial velocity is 0 m/s, the final velocity is 50 m/s, and the time of contact is 0.002 s. Plugging these values into the equation, we get:

F = (0.03 kg * (50 m/s - 0 m/s)) / 0.002 s = 1500 N

Therefore, the average force acted on the ball is 1500 N.

Gravity should not be accounted for in this case because the force acted on the ball is solely due to the golf club striking it.