Question

Two capacitors of capacitance 600 PF and 900PF are connected in series across a 200V supply calculate the effective capacitance of the combination

Answer 1

The effective capacitance of two capacitors of 600 pF and 900 pF connected in series is calculated using the series capacitance formula and is found to be 360 pF.

Step-by-step explanation:

To calculate the effective capacitance of two capacitors connected in series, we use the formula:

1. 1/Cs = 1/C1 + 1/C2 where Cs is the effective series capacitance, C1 is the capacitance of the first capacitor and C2 is the capacitance of the second capacitor.

Given that C1 = 600 pF and C2 = 900 pF, we can calculate the effective capacitance (Cs) as follows:

1. 1/Cs = 1/600 + 1/900
2. 1/Cs = (900 + 600) / (600 * 900)
3. 1/Cs = 1500 / 540000 pF
4. 1/Cs = 1 / 360 pF
5. Cs = 360 pF

Therefore, the effective capacitance of the combination when the two capacitors are connected in series across a 200V supply is 360 pF.