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solve the problem. larry has $3000 to invest and needs $3400 in 16 years. what annual rate of return will he need to get in order to accomplish his goal? (round your answer to two decimals.)

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Final answer:

Larry needs an annual rate of return of approximately 0.80% to grow his $3000 investment to $3400 in 16 years, using the formula for compound interest.

Step-by-step explanation:

To solve the problem of finding the annual rate of return Larry needs to get in order to turn his $3000 investment into $3400 in 16 years, we will use the formula for compound interest:


A = P(1 + r)^n

Where:

  • A is the future value of the investment/loan, including interest
  • P is the principal investment amount ($3000 in this case)
  • r is the annual interest rate (decimal)
  • n is the number of years the money is invested (16 years in this case)

We need to find the rate r that will make A equal to $3400 after 16 years. Therefore:

3400 = 3000(1 + r)^16

Dividing both sides by 3000 gives:

1.1333 = (1 + r)^16

Now we apply the nth root to both sides to solve for (1 + r):

(1 + r) = (1.1333)^(1/16)

After calculating the 16th root, we get:

(1 + r) ≈ 1.00797

Then we subtract 1 from both sides to find r:

r ≈ 0.00797

To express this as a percentage, we multiply by 100:

Annual rate of return ≈ 0.797%

Rounded to two decimals, Larry will need an annual rate of return of 0.80% to achieve his goal of $3400 in 16 years.

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