Question

An object is thrown down from a tall building with an initial velocity of 2 m/s. How fast is it going after 5 seconds of free fall?

Answer 1

Step-by-step explanation:

Given:

V₀ = 2 m/s

g = 9.8 m/s²

t = 5 s

____________

V - ?

Axis OX direct vertically down. Then:

V = Vₓ = V₀ₓ + g·t

V = 2 + 9.8*5 = 51 m

Answer 2

Answer: Vf = Vi + A(t)

Vf= -2+ (-9.8)(5)

Vf = -51 m/s

Step-by-step explanation:

The final velocity is equal to the initial velocity plus the acceleration multiplied by the time

(-9.8) is used for the acceleration for this question because that is the speed at which things in free fall accelerate when they are on earth

-2 is used as the initial velocity because the ball was thrown in the negative direction which is down.

The time of 5 was given in the question so you can plug it in for time