Question

The vapor pressure of solid iodine at 25°C is 0.001864atm . Calculate the vapor pressure in mmHg and torr . Be sure your answers have the right number of significant digits.

Answer 1

To convert the vapor pressure of solid iodine at 25°C from atm to mmHg and torr, multiply by 760 mmHg/atm, resulting in both the mmHg and torr value as 1.417, considering 4 significant figures.

Step-by-step explanation:

The vapor pressure of solid iodine at 25°C is given as 0.001864 atm. To convert this pressure to mmHg and torr, we can use the conversion factors, knowing that 1 atm is equivalent to 760 mmHg, which is also equivalent to 760 torrs (since 1 torr = 1 mmHg). Therefore:

Vapor pressure in mmHg = 0.001864 atm × (760 mmHg / 1 atm) = 1.41664 mmHg

Vapor pressure in torr = 1.41664 torr (since 1 torr = 1 mmHg)

Considering significant digits, since the given vapor pressure of iodine has 4 significant digits, our answers should also reflect the same precision:

• Vapor pressure in mmHg = 1.417 mmHg
• Vapor pressure in torr = 1.417 torr