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10 votes
10 votes
G(x) = 2x - 1

h(x) = 1-g(x)
the functions g and h are defunded above. What is the value of h(0)

User Kellee
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1 Answer

13 votes
13 votes

Answer:

2

Step-by-step explanation:

Since h (x) = 1 − g (x), substituting 0 for x yields h (0) = 1 − g (0). Evaluating g (0) gives g (0) = 2(0) − 1 = −1. Therefore, h (0) = 1 − (−1) = 2.

User BobB
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