Question

Silver bromide was prepared by reacting 200.0 grams of magnesium bromide and an adequate amount of silver nitrate. Write the balanced chemical equation and calculate the percent yield if 375.0 grams of silver bromide was obtained from this double displacement reaction.

Answer 1

The balanced chemical equation for the reaction is 2AgNO3 + MgBr2 → 2AgBr + Mg(NO3)2. The theoretical yield of AgBr is 1.997 mol. The percent yield is calculated to be 187.81%.

Step-by-step explanation:

The balanced chemical equation for the reaction between magnesium bromide (MgBr2) and silver nitrate (AgNO3) is:

2AgNO3 + MgBr2 → 2AgBr + Mg(NO3)2

To calculate the percent yield, we first need to find the theoretical yield, which is the maximum amount of silver bromide (AgBr) that can be obtained from the reaction. The molar mass of AgBr is 187.77 g/mol, so the theoretical yield can be calculated as:

Theoretical Yield = (375.0 g AgBr) / (187.77 g/mol) = 1.997 mol AgBr

Next, we need to find the actual yield, which is given as 375.0 grams of AgBr. To calculate the percent yield, we use the formula:

Percent Yield = (Actual Yield / Theoretical Yield) * 100

Percent Yield = (375.0 g / 1.997 mol) * 100 = 187.81%